b[b(b-2)-4]+1=

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Solution for b[b(b-2)-4]+1= equation: 


Simplifying
b[b(b + -2) + -4] + 1 = 0

Reorder the terms:
b[b(-2 + b) + -4] + 1 = 0
b[(-2 * b + b * b) + -4] + 1 = 0
b[(-2b + b2) + -4] + 1 = 0

Reorder the terms:
b[-4 + -2b + b2] + 1 = 0
[-4 * b + -2b * b + b2 * b] + 1 = 0
[-4b + -2b2 + b3] + 1 = 0

Reorder the terms:
1 + -4b + -2b2 + b3 = 0

Solving
1 + -4b + -2b2 + b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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